Answer: f = 3310 Hz
Explanation: length of auditory canal (pipe) = 2.5cm =0.025m
Since we are assuming it to be an open ended pipe (opened at one end, closed at the other), the length of air is related to wavelength of sound at fundamental frequency is given below as
l = λ/4
λ = 4l
λ = 4(0.025)
λ = 0.1 m
But v=fλ where v is the speed of sound in the ear = 331 m/s and f = frequency of sound.
331 = f(0.1)
f = 331/0.1
f = 3310 Hz