Explanation:
Using Coulomb's law, the relation between force and charge is as follows.
F = [tex]k \frac{q_{1}q_{2}}{r^{2}}[/tex]
In the given case, [tex]q_{1} = q_{2}[/tex] = q
Hence,
F = [tex]k \frac{q^{2}}{r^{2}}[/tex]
[tex]q^{2} = \frac{F \times r^{2}}{k}[/tex]
Squaring on both the sides, we get
q = [tex]r \times \sqrt{\frac{F}{k}}[/tex]
= [tex]1.3 m \times \sqrt{\frac{2.2 N}{9 \times 10^{9}}}[/tex]
= [tex]6.422 \times 10^{-5}[/tex] C
= [tex]64.22 \times 10^{-6}\mu C[/tex]
Thus, we can conclude that magnitude of the charge on each grape is [tex]64.22 \times 10^{-6}\mu C[/tex].
