Answer:
The coin travels 1.8348 meters above its point of release.
Explanation:
Initial speed = 6 m/s (Assumed vertical speed as not stated in question)
Final Speed = 0 m/s (at the highest point in air)
Acceleration due to gravity = -9.81 m/s^2
Equation of motion used:
[tex](V_f)^2 - (V_i)^2 = 2 *a * s[/tex]
[tex]0^2 - 6^2 = 2 * (-9.81) * s[/tex]
s = 1.8348 m
Thus, the coin will travel 1.8348 meters up to its highest point in the air.
