the maximum possible length of the pencil is 13 inches
Step-by-step explanation:
Here we have , An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. We need to find What is the maximum possible length of the pencil . Let's find out:
We know that maximum length which can be fitted in envelope will be the length of diagonal of envelope . So
By Pythagoras theorem
[tex]Diagonal^2 = length^2 +breadth^2[/tex]
⇒ [tex]Diagonal^2 = length^2 +breadth^2[/tex]
⇒ [tex]Diagonal^2 =5^2 +12^2[/tex]
⇒ [tex]Diagonal^2 =25 +144[/tex]
⇒ [tex]Diagonal^2 = 169[/tex]
⇒ [tex]\sqrt{Diagonal^2} = \sqrt{169}[/tex]
⇒ [tex]Diagonal= 13 inch[/tex]
Therefore, the maximum possible length of the pencil is 13 inches .
