Respuesta :
Answer:
The acceleration of Kaya is [tex]1.41\ m/s^2[/tex].
Explanation:
Given that,
Initial speed of Kaya, u = 14 m/s
Final speed of Kaya, v = 5.5 m/s
Time, t = 6 s
We need to find Kaya's acceleration. We know that it is given by the change in speed per unit time. Its formula is given by :
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{14\ m/s-5.5\ m/s}{6\ s}\\\\a=1.41\ m/s^2[/tex]
So, the acceleration of Kaya is [tex]1.41\ m/s^2[/tex]. Hence, this is the required solution.
The acceleration should be 1.41 m/s^2.
Calculation of the acceleration:
Since
Initial speed of Kaya, u = 14 m/s
Final speed of Kaya, v = 5.5 m/s
And,
Time, t = 6 s
So, the following formula should be used for determining the acceleration.
a = v - u /t
= 14 - 5.5 /6
= 1.41 m/s^2
hence, The acceleration should be 1.41 m/s^2.
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