Respuesta :
5.5 litres is the volume of chlorine gas at 38oC and 1.63 atm is needed to react completely with 10.4 grams of sodium to form sodium chloride.
Explanation:
data given:
mass of sodium chloride in reaction = 10.4 grams
atomic mass of one mole of NaCl = 58.44 grams/mole
balanced equation for the reaction:
2Na (s) + Cl2 (g) 2NaCl (s).
number of moles = [tex]\frac{mass}{atomic mass of one mole}[/tex]
= [tex]\frac{10.4}{58.44}[/tex]
= 0.17 moles of Na in the reaction.
from the reaction,
2 moles of Na reacted with 1 mole of Cl2
0.17 moles of Na reacted with x moles
[tex]\frac{2}{1}[/tex] = [tex]\frac{0.7}{x}[/tex]
x = 0.35 moles of chlorine gas reacted to form NaCl
To know the volume following equation will be used:
PV = nRT
V = [tex]\frac{nRT}{P}[/tex] R=0.0826 L atm/Mole.K, T = 311.15, P= 1.63 atm, n= 0.35 moles
V = [tex]\frac{0.35 x 0.0826x311.15}{1.63}[/tex]
V = 5.5 litres is the volume of chlorine gas formed at given conditions.
