Answer:
a) Exponential decay
b,) The parent function is shifted up 1 unit.
Step-by-step explanation:
Assuming your function is
[tex]y = ( \frac{1}{3} )^{x} + 1[/tex]
Then we can compare this to:
[tex]y = {b}^{x} + c[/tex]
If
[tex]0 \: < \: b \: < 1[/tex]
then y is an exponential decay function.
If |b|>1, then y is an exponential growth.
We can see that:
[tex]0 \: < \: \frac{1}{3} \: < \: 1[/tex]
Therefore the given function is an exponential decay.
The parent function is shifted up 1 unit.
