Question 9a)
We want to rewrite
[tex]9.7 \times {10}^{4} [/tex]
as a regular number.
The given notation is called the scientific notation.
In this format, the number is written in the form k×10ⁿ where 0<k<1 and n is an integer.
To convert to standard notation format we multiply k repeatedly by 10, n-times.
This implies that:
[tex]9.7 ×10^4=9.7*10*10*10*10[/tex]
[tex]9.7 \times 10000 = 97000[/tex]
Question 9b)
[tex]7 \times {10}^{5} = 7 \times 100000 = 700000[/tex]
Question 9c)
[tex]8.97 \times {10}^{7} [/tex]
[tex]8.97 \times 10000000 = 89700000[/tex]
Question 9d)
[tex]3.2 \times {10}^{10} \\ 3.2 \times 10000000000 = 32000000000[/tex]
Question 10a)
To find the square root of a perfect square, we look for a number that multiplies itself to give the number in question.
For [tex]\sqrt{16}[/tex] we have 4×4=16[/tex]
This implies that:
[tex] \sqrt{16} = \sqrt{ {4}^{2} } = 4[/tex]
Question 10b)
Also 13×13=169
This implies that;
[tex] \sqrt{169} = \sqrt{ {13}^{2} } = 13[/tex]
Question 10c)
Again 8×8=64
This my that:
[tex] \sqrt{64} = \sqrt{ {8}^{2} } = 8[/tex]
Question 10 d)
Finally, 20×20=400
Therefore
[tex] \sqrt{400} = \sqrt{ {20}^{2} } = 20[/tex]
