Answer:
30 liters
Explanation:
Since a pressure, volume, and temperature is given, this problem involves the combined gas law:
[tex]\frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2} }[/tex]
1. First, identify the given values. Make sure they are all the same units, and temperature is always in Kelvin.
Your initial values:
P1 = 12 atm
V1 = 23 L
T1 = 200 K
Your final values:
P2 = 14 atm
V2 = ?
T2 = 300 K
2. Now, plug it into the combined gas law formula. If it is easier for you, then you can rearrange the formula for V2.
[tex]\frac{12 * 23}{200} = \frac{14 * V_{2} }{300}[/tex]
3. Lastly, solve for V2.
[tex]\frac{12 * 23}{200} = \frac{14 * V_{2} }{300}[/tex]
1.38*300 = 14V2
414 = 14V2
V2 = 29.57142857142857
With sig figs, your final volume would be: 30L
Answer:
29.57L
Explanation:
The following were obtained from the question:
P1 (initial pressure) = 12atm
V1 (initial volume) = 23L
T1 (initial temperature) = 200K
P2 (final pressure) = 14atm
T2 (final temperature) = 300K
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume other wise called the new volume of the gas can easily be obtained as follow:
P1V1/T1 = P2V2/T2
12 x 23/200 = 14 x V2/300
Cross multiply to express in linear form as shown below:
200 x 14 x V2 = 12 x 23 x 300
Divide both side by 200 x 14
V2 = (12 x 23 x 300) /(200 x 14)
V2 = 29.57L
Therefore, the new volume of the gas is 29.57L
