Answer:
[tex]\large \boxed{\text{FALSE}}[/tex]
Explanation:
The empirical formula is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of U to O.
Data:
Mass of U = 2.38 g
Mass of UₓOy = 2.806 g
Calculations
1. Calculate the mass of O
Mass of O = 2.806 g - 2.38 g = 0.426 g
2. Calculate the moles of each element
[tex]\text{Moles of U} = \text{2.38 g U} \times \dfrac{\text{1 mol U}}{\text{238.03 g U}} = \text{0.009 999 mol U}\\\\\text{Moles of O} = \text{0.426 g O} \times \dfrac{\text{1 mol O}}{\text{16.00 g O }} = \text{0.026 62 mol O}[/tex]
3. Calculate the molar ratio of the elements
Divide each number by the smallest number of moles
U:O = 1:2.663 = 3:7.988 ≈ 3:8
[tex]\text{The simplest molar ratio of U:O is $\large \boxed{\mathbf{3:8}}$}[/tex]
