I didn’t realize it had a second part until after the fact.

Step-by-step explanation:
Let [tex] log_{16}(64) = x[/tex]
[tex] => {16}^{x} = 64[/tex]
[tex] => {4}^{2x} = {4}^{3} [/tex]
[tex] => 2x = 3[/tex]
since bases are same exponents are equal.
[tex]x = \frac{3}{2} [/tex]
option C