in an examination, Adenike obtained 19marks more than musa.if adenike had obtained one and half times her own mark,she would have score 6 marks more than twice musa mark.find the mark score by each of them.

First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as

3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;

d = 19 + m ———(1)

3d/2 = 6 + 2m ———(2)

Substitute for the value of d into equation (2), if d = 19 + m

(3{19 + m})/2 = 6 + 2m

By cross multiplication we now have

3(19 + m) = 2(6 + 2m)

57 + 3m = 12 + 4m

We collect like terms and we have

57 - 12 = 4m - 3m

45 = m

We now substitute for the value of m into equation (1)

d = 19 + m

d = 19 + 45

d = 64

So Adenike scored 64 marks while Musa scored 45 marks

in an examination, Adenike obtained 19marks more than musa.if adenike had obtained one and half times her own mark,she would have score 6 marks more than twice musa mark.find the mark score by each of them.​

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in an examination, Adenike obtained 19marks more than musa.if adenike had obtained one and half times her own mark,she would have score 6 marks more than twice musa mark.find the mark score by each of them.