Answer:
The partial pressure of [tex]C_6H_6[/tex] when the valve is opened is 328.6 Torr.
Explanation:
Initial pressure of the [tex]C_6H_6=P_1=608.0 Torr[/tex]
Initial volume of the [tex]C_6H_6=V_1=1000 mL[/tex]
After opening the valve :
Final pressure or partail pressure of the [tex]C_6H_6=P_2[/tex]
Final volume of the [tex]C_6H_6=V_2=1000 mL+850.0 mL=1850.0 mL[/tex]
[tex]P_1V_1=P_2V_2[/tex] ( Boyle's law)
[tex]P_2=\frac{608.0 Torr \times 1000 mL}{1850.0 mL}=328.6 Torr[/tex]
The partial pressure of [tex]C_6H_6[/tex] when the valve is opened is 328.6 Torr.
