Respuesta :
Answer:
direction is 43.495 degrees south of west.
Explanation:
given data
larger tug exert force = 20 percent greater than smaller tug
angle = 35 degrees south of west
solution
The smaller tug must pull in south west direction at angle that from north - south component of 2 force that cancel each other out
we take smaller tug is pulling with a force F
so
Smaller tug express as = F sin(α)
and
Larger tug is (F + 0.20 F) sin(35 degrees) < 20% larger than smaller tugboat and 0 degree direction is directly west
so here we can say
Smaller tug + Larger tug = Fsinα + (F + 0.20 F) sin(35 ) = 0
here α angle is going to be south of west
so it will be a negative angle.
and
now we Divide F of the entire equation so
it will be as
sinα + (1 + 0.20 ) sin(35 ) = sinα + 0.6596 = 0
sinα + 0.6883 = 0
sinα = -0.6883
α = -43.495 degree
so direction is 43.495 degrees south of west.
The direction is 43.495 degrees south of west.
Given:
larger tug exert force = 20 percent greater than smaller tug
angle = 35 degrees south of west
Calculation for direction:
The smaller tug must pull in south west direction at angle that from north - south component of 2 force that cancel each other out
Let us consider smaller tug is pulling with a force F
Thus,
Smaller tug = F sin(α)
and
Larger tug = (F + 0.20 F) sin(35 degrees) < 20% larger than smaller tugboat and 0 degree direction is directly west.
Therefore,
Smaller tug + Larger tug = Fsinα + (F + 0.20 F) sin(35 ) = 0
Where, α angle is going to be south of west, so it will be a negative angle.
Solving for α:
sinα + (1 + 0.20 ) sin(35 ) = sinα + 0.6596 = 0
sinα + 0.6883 = 0
sinα = -0.6883
α = -43.495 degree
So direction is 43.495 degrees south of west.
Find more information about Direction here:
brainly.in/question/36787140
