Answer:
x=1 or x=5
Step-by-step explanation:
Given Equation
[tex]x^2-6x+5[/tex]
Making the equation in standard form:
[tex]x^2-6x+5=0[/tex]
Making the factor of the equation:
[tex]x^2-x-5x+5=0[/tex]
Taking common from the equation:
[tex]x(x-1)-5(x-1)=0[/tex]
[tex](x-1)(x-5)=0[/tex]
Equating the values:
[tex]x-1=0\\\\x=1[/tex]
OR
[tex]x-5=0\\\\x=5[/tex]
Answer: x = 5, x = 1
Step-by-step explanation:
x² - 6x + 5
a=1 b=-6 c=5
The quadratic formula is:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(1)(5)}}{2(1)}\\\\\\x=\dfrac{6\pm\sqrt{36-20}}{2}\\\\\\x=\dfrac{6\pm\sqrt{16}}{2}\\\\\\x=\dfrac{6\pm4}{2}\\\\\\x=\dfrac{6+4}{2}\qquad \qquad x=\dfrac{6-4}{2}\\\\\\x=\dfrac{10}{2}\qquad \qquad \qquad x=\dfrac{2}{2}\\\\\\\large\boxed{x=5}\qquad \qquad \quad \large\boxed{x=1}[/tex]
