Answer:
The amount of heat transfer is 21,000J .
Explanation:
The equation form of thermodynamics is,
ΔQ=ΔU+W
Here, ΔQ is the heat transferred, ΔU is the change in internal energy, and W is the work done.
Substitute 0 J for W and 0 J for ΔU
ΔQ = 0J+0J
ΔQ = 0J
The change in internal energy is equal to zero because the temperature changes of the house didn’t change. The work done is zero because the volume did not change
The heat transfer is,
ΔQ=Q  (in ) −Q (out )
Substitute 19000 J + 2000 J for Q(in) Â and 0 J for Q(out)
ΔQ=(19000J+2000J)−(0J)
=21,000J
​Thus, the amount of heat transfer is 21,000J .
​
Answer:
The thermal energy of the house is [tex]E_{thermal} = 0J[/tex]
The magnitude of the energy transfer is [tex]\Delta Q = 21,000J[/tex]
Explanation:
From the question we are told that
       The energy content is  [tex]E_c = 19000J[/tex]
        The energy through sunshine is  [tex]E_s = 2000J[/tex]
Generally the first law of thermodynamics can be mathematically represented as
         [tex]\Delta Q = \Delta U + W[/tex]
Where [tex]\Delta Q[/tex] is the heat transferred
      [tex]\Delta U[/tex] is the change in internal energy with is = 0J  the temperature of the house did not change
      [tex]W[/tex] is the workdone which = 0J This because the volume of the air in the house  did not change
  Therefore  [tex]\Delta Q = 0J + 0J[/tex]
               [tex]= 0J[/tex]
And this is equivalent to the thermal energy of the house [tex]E_{thermal}[/tex]
Therefore
     [tex]E_{thermal}[/tex] = 0J
Now the  heat transfer from outside to inside can be mathematically  represented as
       [tex]\Delta Q = Q_{in} - Q_ {out}[/tex]
Now [tex]Q_{in}[/tex] = 19000 + 2000
       [tex]= 21,000 J[/tex]
This because both the energy of the natural and the sunshine are supplied to the house
And Â
      [tex]Q_{out][/tex] = 0 this is because there are no transfer of heat to the surrounding
  Hence
       [tex]\Delta Q = 21000 - 0[/tex]
          [tex]= 21000J[/tex]
