Answer:
Length:15 cm
Width: 12 cm
Step-by-step explanation:
Let
L ----> the length of the rectangular canvas
W ---> the width of the rectangular canvas
we know that
The width is 4/5 of the length
so
[tex]W=\frac{4}{5}L[/tex] ----> equation A
we have
[tex]L=(6x-3)\ cm[/tex]
[tex]W=(2x+6)\ cm[/tex]
substitute the given values in equation A
[tex](2x+6)=\frac{4}{5}(6x-3)[/tex]
solve for x
[tex]10x+30=24x-12\\24x-10x=30+12\\14x=42\\x=3[/tex]
Find the dimensions of the canvas
substitute the value of x
[tex]L=6(3)-3=15\ cm[/tex]
[tex]W=2(3)+6=12\ cm[/tex]