On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about W/m². What is the electromagnetic energy contained in 5.20 m³ of space just above the earth's surface?

Respuesta :

Answer:

1.907 x 10⁻⁵ J.

Explanation:

Given,

Volume of space, V = 5.20 m³

Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².

Electromagnetic energy = ?

[tex]E = \mu V[/tex]

[tex]E = (\dfrac{S}{c})\times V[/tex]

where c is the speed of light.

[tex]E = (\dfrac{1.1\times 10^3}{3\times 10^8})\times 5.20[/tex]

[tex]E = 1.907\times 10^{-5}\ J[/tex]

Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.