Answer:
6.11°
yes
Explanation:
v = 170 km/h = 47.2 m/s
vx = v cos θ
vy = v sin θ
In horizontal direction, there is no acceleration.
vx t = 11.9
In vertical direction:
2.5 - 0.91 = vy t + 0.5 gt²
⇒1.59 = 11.9 tan θ + 4.9×0.25²× sec²θ (∵g = 9.8 m/s²)
⇒1.59 = 11.9 tan θ + 4.9×0.25²× (1+tan²θ)
Solving for θ will give the result 6.11°
Displacement in x-direction
t = 0.375 s
vx t = 11.9
47.2 cos (6.11°) 0.375 s = 17.6 -11.9 = 5.7 m
The outline is 6.40 m from the net. Thus, the ball will fall in the service box.
