Respuesta :
Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type        possible genotypes
Type A Â Â Â Â Â Â Â Â Â Â Â Â AA, AO
Type B Â Â Â Â Â Â Â Â Â Â Â Â BB, BO
Type AB Â Â Â Â Â Â Â Â Â Â Â Â Â AB
Type O Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO Â for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired       homozygous smooth haired
P gen        SS         x        ss
F1 gen. Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Ss
phenotype: Â Â Â Â Â Â Â Â Â Â wire haired
1. Ralph has type B blood and his wife Rachel has to type A blood. They are very shocked to hear that their baby has type O blood, and think that a switch might have been made at the hospital - yes these can be theirs
2. the phenotype of the F1 generation would be wired hair. The genotype is Ss. The ratio is 3:1.
Blood Type
The genotype of A blood type = I​​​​​​A I​​​​​​A, I​​​​​​A i and the genotype of B blood type = I​​​​​​B I​​​​​​B, I​​​​​​B i. These are heterozygotes in their blood genotype.
Cross:     I​​​​​​Ai X I​​​​​​Bi
Punnett square :
    I​​​​​​A     i
I​​​​​​B  AB    B
i  A     ii (O)
The genotype of O blood type = ii, this is possible
2.
It is given that wire hair (S) is dominant to smooth (s) then wired hair genotype would be - SS. The smooth hair genotype would be - ss
Cross: SS X Ss
Punnett:
   S   S
s  Ss  Ss
s  Ss   Ss
Thus, the offspring have wired hair as S dominant over s.
Learn more about the Blood group:
https://brainly.com/question/7453243