I need help now pls ?!!!

Step-by-step explanation:
[tex] \frac{3}{x} = \frac{4x + 3}{ {x}^{2} } \\ \\ \frac{3x}{ {x}^{2} } = \frac{4x + 3}{ {x}^{2} } \\ \\ 3x = 4x + 3 \\ \\ 3x - 4x = 3 \\ - x = 3 \\ x = - 3[/tex]
[tex] \frac{3}{x} = \frac{4x + 3}{ {x}^{2} } \\ \\ \frac{3x}{ {x}^{2} } = \frac{4x + 3}{ {x}^{2} } \\ \\ 3x = 4x + 3 \\ \\ 3x - 4x = 3 \\ - x = 3 \\ x = - 3 \\ x = - 3, \: \: x = 0 \: is \: an \: extraneous \: \\solution. [/tex]