Answer:
The answer to your question is 510.7 kJ
Explanation:
Data
Q = ?
Volume = 2 L
Temperature 1 = T1 = 19°C
Temperature 2 = T2 = 80°C
Specific heat = 4.186 J/kg°C
Density of water = 1 g/ml
Equation
Q = mC(T2 - T1)
Process
1.- Calculate the mass of water
mass = density x volume
mass = 1 x 2000
mass = 2000 g
2.- Substitute values in the Heat formula
Q = (2000)(4.186)(80 - 19)
-Simplification
Q = (2000)(4.186)(61)
-Result
Q = 510692 J or 510.7 kJ
