Linolenic acid (C18H30O2 - M.W. = 278.42 g/mol) reacts with hydrogen gas according to the equation: C18H30O2 + 3H2 (g) โ†’ C18H36O2 What volume of hydrogen gas, as measured at P = 1.00 atm and T = 273.15 K, is required to react with 10.5 g of linolenic acid in this reaction?

Respuesta :

Answer:

2.53 L is the volume of Hโ‚‚ needed

Explanation:

The reaction is: Cโ‚โ‚ˆHโ‚ƒโ‚€Oโ‚‚ + 3Hโ‚‚ โ†’ Cโ‚โ‚ˆHโ‚ƒโ‚†Oโ‚‚

By the way we can say, that 1 mol of linolenic acid reacts with 3 moles of oxygen in order to produce, 1 mol of stearic acid.

By stoichiometry, ratio is 1:3

Let's convert the mass of the linolenic acid to moles:

10.5 g . 1 mol / 278.42 g ย = 0.0377 moles

We apply a rule of three:

1 mol of linolenic acid needs 3 moles of Hโ‚‚ to react

Then, 0.0377 moles will react with (0.0377 . 3 )/1 = 0.113 moles of hydrogen

We apply the Ideal Gases Law to find out the volume (condition of measure are STP) โ†’ P . V = n . R . T โ†’ V = ( n . R .T ) / P

V = (0.113 mol . 0.082 L.atm/mol.K . 273.15K) 1 atm = 2.53 L