A circular loop (radius of 20 cm) is in a uniform magnetic field of 0.15 T. What angle(s) between the normal to the plane of the loop and the field would result in a flux with a magnitude of ?

Respuesta :

Answer:

The angle other than 90 degrees would result in magnetic flux of non zero magnitude.

Explanation:

The magnetic flux through a given closed area is equal to [tex]\underset{B}{\rightarrow}.\underset{A}{\rightarrow}[/tex].

    Where [tex]\underset{B}{\rightarrow}[/tex] is the magnitude of magnetic flux through loop .

                [tex]\underset{A}{\rightarrow}[/tex] is the area vector of the given loop .

      We know that [tex]\underset{B}{\rightarrow}.\underset{A}{\rightarrow}[/tex] = [tex]\left | A \right |\left | B \right |\cos \theta[/tex],

 Where [tex]\theta[/tex] is the angle made by magnetic field with area vector.

   Area vector of a closed loop is always normal to the plane of the loop .

So from above equation we can deduce that

                  [tex]\theta = \cos^{-1}\frac{\phi }{\left | A \right |\left | B \right |}[/tex]      

      [tex]\phi[/tex] is the magnitude of magnetic flux which is non zero when [tex]\theta[/tex] not equal to 90 degrees.