Answer:
The the angle between the axis of polarization of the light and the transmission axis of the analyzer is 52ā°.
Explanation:
Given;
Iā Ā as incident light intensity
The intensity of a linearly polarized light passing through a polarizer is given by Malus' law:
I = IāCosĀ²Īø
where;
I is the intensity after passing through the analyzer
Īø is the the angle between the axis of polarization of the light and the transmission axis of the analyzer.
If 38% of the total intensity is transmitted, then I = 38% of Iā = 0.38Iā
0.38Iā = IāCosĀ²Īø
0.38 = CosĀ²Īø
CosĪø = ā0.38
CosĪø = 0.6164
Īø Ā = Cosā»Ā¹ (0.6164)
Īø Ā = 51.95Ā° = 52ā°
Therefore, the angle between the axis of polarization of the light and the transmission axis of the analyzer to allow 38% of the total intensity to be transmitted is 52ā°.
