Answer:
[tex]\frac{-1\±\sqrt{21} }{10}[/tex]
Step-by-step explanation:
First let's multiply out the equation
[tex]8x-4(-5x-2)=12x[/tex]
[tex]-40x^2-16x+20x+8=12x[/tex]
[tex]-40x^2-8x+8[/tex]
We can't factor so I will use the quadratic formula
[tex]\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\frac{8\±\sqrt{(-8)^2-4(-40)(8)} }{2(-40)}[/tex]
[tex]\frac{8\±\sqrt{64+1280} }{-80}[/tex]
[tex]\frac{8\±\sqrt{1344} }{-80}[/tex]
[tex]\frac{8\±\ 8 \sqrt{21} }{-80}[/tex]
[tex]\frac{-1\±\sqrt{21} }{10}[/tex]
