contestada

During a recent winter storm, bales of hay had to be dropped from an airplane to a herd of cattle below. Assume the airplane flew horizontally at an altitude of 180 m with a constant velocity of 50 m/s and dropped one bale of hay every two seconds. It is reasonable to assume that air resistance will be negligible for this situation. As the bales are falling through the air, what will happen to their distance of separation?

Respuesta :

lublana

Answer:

203 m

Explanation:

We are given that

Height=h=180 m

Initial velocity,u=0

Velocity,v=50 m/s

We have to find the separation of  bales.

We know that

[tex]s=ut+\frac{1}{2}gt^2[/tex]

Where [tex]g=9.8 m/s^2[/tex]

[tex]180=0+\frac{1}{2}(9.8)t^2[/tex]

[tex]t^2=\frac{180\times 2}{9.8}[/tex]

[tex]t=\sqrt{\frac{180\times 2}{9.8}}=6.06 s[/tex]

Bale dropped every two seconds

Therefore, time=6.06-2=4.06 s

Distance=[tex]v\times t[/tex]

[tex]d=50\times 4.06=203 m[/tex]

Otras preguntas