Answer:
N(24, 3.46)
Step-by-step explanation:
We are given the following in the question:
Percentage of family homes having front poach = 50%
[tex]p = 50\% = 0.50[/tex]
Sample size, n = 48
Normal approximation to the given distribution:
[tex]\mu = np = 48(0.50) = 24[/tex]
[tex]\sigma = \sqrt{np(1-p)} = \sqrt{48(0.50)(1-0.50)} = 3.46[/tex]
Thus, the distribution of single family homes is best approximated by the normal distribution N(24, 3.46) where mean is 24 and standard deviation is 3.46
