Respuesta :
Answer: The mass of acetic acid that can be produced is 30.24 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For acetaldehyde:
Given mass of acetaldehyde = 22.2 g
Molar mass of acetaldehyde = 44 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of acetaldehyde}=\frac{22.2g}{44g/mol}=0.504mol[/tex]
- For oxygen gas:
Given mass of oxygen gas = 12.6 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{12.6g}{32g/mol}=0.394mol[/tex]
The given chemical equation follows:
[tex]2CH_3CHO(l)+O_2(g)\rightarrow 2CH_3COOH(l)[/tex]
By Stoichiometry of the reaction:
2 moles of acetaldehyde reacts with 1 mole of oxygen gas
So, 0.504 moles of acetaldehyde will react with = [tex]\frac{1}{2}\times 0.504=0.252mol[/tex] of oxygen gas
As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, acetaldehyde is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of acetaldehyde produces 2 moles of acetic acid
So, 0.504 moles of acetaldehyde will produce = [tex]\frac{2}{2}\times 0.504=0.504moles[/tex] of acetic acid
Now, calculating the mass of acetic acid from equation 1, we get:
Molar mass of acetic acid = 60 g/mol
Moles of acetic acid = 0.504 moles
Putting values in equation 1, we get:
[tex]0.504mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.504mol\times 60g/mol)=30.24g[/tex]
Hence, the mass of acetic acid that can be produced is 30.24 grams
