Respuesta :
Answer:
- train: 40 kph
- plane: 140 kph
Step-by-step explanation:
Let t represent the speed of the train in km/h. Then 4t-20 is the speed of the plane. Travel times are the same, so we can use the formula ...
 time = distance/speed
and equate the travel times.
 110/t = 385/(4t-20)
Cross multiplying gives ...
 110(4t -20) = 385t
 440t -2200 = 385t . . . . . eliminate parentheses
 55t -2200 = 0 . . . . . . . . . subtract 385t
 t -40 = 0 . . . . . . . . . divide by 55
 t = 40 . . . . . . . . . . . add 40; train's speed is 40 kph
 4t -20 = 140 . . . . . . find plane's speed; 140 kph
The train's speed is 40 km/h; the plane's speed is 140 km/h.
_____
Check
Train's travel time = 110 km/(40 km/h) = 2.75 h.
Plane's travel time = 385 km/(140 km/h) = 2.75 h.
Answer:
Two identical trains, Train A and Train B, are traveling along parallel rails.
The speed of Train A is 88 km/hr, and the speed of Train B is 96 km/hr. Based on this information, which of the following statements is true?
A.
Train B has more kinetic energy than Train A.
B.
Train A has more kinetic energy than Train B.
C.
The trains have the same kinetic energy.
D.
Neither train has any kinetic energy.
Step-by-step explanation: