Hi can someone help me out with this problem.

Answer:
third side = 9
Step-by-step explanation:
Using Pythagoras' identity on the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let the third side be x, then
x² + 40² = 41², that is
x² + 1600 = 1681 ( subtract 1600 from both sides )
x² = 81 ( take the square root of both sides )
x = [tex]\sqrt{81}[/tex] = 9
The third side is 9
Answer: The answer is 9 units
Step-by-step explanation: What we have in the question is a right angled triangle. The hypotenuse (41 units) has been given as well as one of the other two sides (40 units).
The Pythagoras theorem states that;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse and AB and BC are the other two sides. We now have
41^2 = 40^2 + BC^2
1681 = 1600 - BC^2
Subtract 1600 from both sides of the equation
81 = BC^2
Add the square root sign to both sides of the equation
9 = BC
Therefore the exact length of the third side is 9 units