Which function is shown in the graph below? On a coordinate plane, a curve goes through (0.33, negative 1), (1, 0), and (3, 1). y = log Subscript 0.4 Baseline x y = log Subscript 1 Baseline x y = log Subscript 3 Baseline x y = log Subscript 10 Baseline x

Respuesta :

Answer:

y = ㏒₃ x

Step-by-step explanation:

Given: the points (0.33, -1), (1, 0), and (3, 1)

We will check which function goes through the previous points

we will use the point (3,1)

1) y = ㏒₀.β‚„ x

㏒₀.β‚„ x = ㏒₀.β‚„ 3 = -1.199 β‰  1

2) y = ㏒₁ x

㏒₁ x = ㏒₁ 3 β‡’ unlogic Β condition

3) y = ㏒₃ x

㏒₃ x = ㏒₃ 3 = 1

4) y = ㏒₁₀ x

㏒₁₀ x = ㏒₁₀ 3 = 0.477 β‰  1

So, from the previous explanation:

The function is y = ㏒₃ x

Another solution;

by drawing the four function we will find which function goes through the points (0.33, -1), (1, 0), and (3, 1)

See the attached figure.

So, the answer is y = ㏒₃ x

Ver imagen Matheng

Answer:

The answer is C on ed.

Step-by-step explanation: