Answer:
6 is the stoichiometric factor, that is the number of moles of [tex]Na_2S_2O_3[/tex] reacting with one mole of [tex]KIO_3[/tex].
Explanation:
[tex]IO_3^{-}(aq) + 5 I^-(aq) + 6 H^+(aq)\rightarrow 3 I_2(aq) + 3 H_2O(l)[/tex] ..[1]
[tex]I_2(aq) + 2 S_2O_3^{2-}(aq)\rightarrow 2 I^-(aq) + S_4O_6^{2-}(aq)[/tex]..[2]
[1] + 3 × [2]
Overall reaction of the process:
[tex]IO_3^{-}(aq) + 6 H^+(aq)+6S_2O_3^{2-}(aq)\rightarrow 3 H_2O(l)+I^-(aq)+3 S_4O_6^{2-}(aq)[/tex]
According to stoichiometry of reaction above, 6 moles of [tex]S_2O_3^{2-}[/tex] reacts with 1 mole of [tex]IO_3^{-}[/tex].
6 is the stoichiometric factor, that is the number of moles of [tex]Na_2S_2O_3[/tex] reacting with one mole of [tex]KIO_3[/tex].
