Respuesta :
Answer:
867 N
Explanation:
Given:
Mass of the aircraft (m) = 200,000 kg
Displacement of the aircraft (d) = 100 m
Time taken (t) = 53 s
Coefficient of friction between the tires and concrete (μ) = 0.02
Number of police officers (n) = 60
Initial velocity of aircraft (u) = 0 m/s
Now, using equation of motion, we can find the acceleration of the aircraft.
The equation of motion is given as:
[tex]d=ut+\frac{1}{2}at^2[/tex]
Here, 'a' is the acceleration of the aircraft.
Plug in the given values and solve for 'a'. This gives,
[tex]100=0+\frac{1}{2}a(53)^2\\\\a=\frac{200}{2809}= 0.07\ m/s^2[/tex]
Now, the frictional force is given as:
[tex]f=\mu N=\mu mg=0.02\times 200000\times 9.8=39200\ N[/tex]
Now, let the force of pull of one police be 'F'.
So, the total force of pull of 60 officers = 60F
Now, the net force acting on the aircraft is given as:
[tex]F_{net}=60F-f\\\\F_{net}=60F-39200[/tex]
From Newton's second law, the net force acting on the aircraft is equal to the product of mass and acceleration. So,
[tex]F_{net}=ma\\\\60F-39200=200000\times 0.07\\\\60F=14000+39200\\\\60F=53200\\\\F=\frac{53200}{60}=866.67\approx 867\ N[/tex]
Therefore, the force with which each officer pulled on the plane is 867 N.