Answer:
G=(A^3 + B) * 4-c^2
cobegin
p1: A^3
P2:C^2
P3: p1 +B
P4:P3*4
P5:P4-P2
coend
At first, A^3 will be solved based on FCFS, then C^2, as per BODMAS rule, and power is solved at first. Then Bracket, and hence A^3+ B and then (A^3 + B) *4
And finally, (A^3 +B) *4 -c^2 or minus. And above, only one operation is performed at one time, and that is because we have only one processor. And we are assuming here FCFS and BODMAS Rules.
Explanation:
Please check the answer section.
