Answer:
0.849
Step-by-step explanation:
Number of caramel Chocolates= 6 Chocolates
Number of nut Chocolates= 5 Chocolates
Number of nougat= 4 chocolates
Total number of chocolates= 15
so, we have to find the probability of randomly selected 3 chocolates that are nuts
When first chocolate is drawn
P(nut chocolates)= [tex]\frac{5}{15}[/tex]
Now second chocolate is drawn
P(nut chocolates)=[tex]\frac{4}{14}[/tex]
When the third chocolate is drawn
P(nut chocolates)= [tex]\frac{3}{13}[/tex]
Total probability =[tex]\frac{5}{15}[/tex]+[tex]\frac{4}{14}[/tex] +[tex]\frac{3}{13}[/tex]
Total probability= 0.849
Hence, the correct answer is 0.849
