Answer:
F(b) =2142.106N
Explanation:
Given the following data
Volume is 3.78L which is 1 gallon
Therefore, 58gallons = 3.78×58 = 219.24L
Buoyant force F(b) = V(s) × d × g
Where V(s) = submerged volume = 219.24L = 0.21924m³
d = density of water = 997kg/m³
g = acceleration due to gravity = 9.8m/s²
Therefore F(b) = 0.21924m³× 997kg/m×9.8m/s²
F(b) =2142.106N
