Answer:
Correct option is (A).
Step-by-step explanation:
Let p = proportion of water samples that exceeded the desired pH level.
A sample of size n = 648 is selected. Of these samples X = 62 exceeded the desired pH levels.
The confidence interval for the population proportion is given by:
[tex]CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\Rightarrow CI=\hat p\pm MOE[/tex]
The MOE or margin of error is estimated difference between the true population parameter value and the sample statistic value.
The information provided is:
MOE = 0.02
[tex]\hat p=\frac{X}{n}=\frac{6}{648}=0.096[/tex]
Compute the 90% confidence interval for the proportion of water samples that exceeds the desired pH level as follows:
[tex]CI=\hat p\pm MOE\\=0.096\pm 0.02\\=(0.076, 0.116)\\\approx(8\%, 12\%)[/tex]
Thus, the 90% confidence interval for the proportion of water samples that exceeds the desired pH level is (8%, 12%).
This confidence interval implies that there is a 90% confidence that the river water exceeds the desired pH level between 8% and 12% of the time studied.
The correct option is (A).