Answer:
Therefore the co-ordinate of the point on the line segment from (-9,-1) to(-9,-10) into a ratio internally is (-9,-7).
Therefore the co-ordinate of the point on the line segment from (-9,-1) to(-9,-10) into a ratio internally is (-9,-19).
Step-by-step explanation:
Given points are (-9,-1) and (-9,-10)
If a point divides the line segment by joining two points (x₁,y₁) and (x₂,y₂) into a ratio m:n internally.
Then the point of the coordinate is [tex](\frac{m.x_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex].
If a line segment is externally divided into a point by joining two points (x₁,y₁) and (x₂,y₂) with m: n ratio.
Then the point of the coordinate is [tex](\frac{m.x_2-nx_1}{m-n},\frac{my_2-ny_1}{m-n})[/tex].
Internally
The co-ordinate of the point is [tex](\frac{(-9)\times2+(-9)\times 1}{2+1},\frac{(-10)\times 2+(-1)\times 1}{2+1})[/tex]
[tex]=(-9,-7)[/tex]
Externally
The co-ordinate of the point is [tex](\frac{(-9)\times2-(-9)\times 1}{2-1},\frac{(-10)\times 2-(-1)\times 1}{2-1})[/tex]
= (-9,-19)
