Answer: The molarity of stock solution of luminol is 1.055 M
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Given mass of luminol = 14.0 g
Molar mass of luminol = 177 g/mol
Volume of solution = 75.0 mL
Putting values in above equation, we get:
[tex]\text{Molarity of stock solution}=\frac{14\times 1000}{177\times 75.0}\\\\\text{Molarity of stock solution}=1.055M[/tex]
Hence, the molarity of stock solution of luminol is 1.055 M