Answer:
Average emf of coil is 58.4 V
Explanation:
Given :
No. of turns [tex]N = 80[/tex]
Area of rectangular coil [tex]A = 0.25 \times 0.40 = 0.1[/tex] [tex]m^{2}[/tex]
Magnetic field [tex]B = 1.10[/tex] T
Time of rotation [tex]\Delta t = 0.06[/tex] sec
From the faraday's law,
Average induced emf = [tex]N\frac{\Delta \phi}{\Delta t}[/tex]
But flux through coil is given by,
[tex]\phi = B A \cos \theta[/tex]
So we write above equation,
Average induced emf = [tex]\frac{NBA( \cos \theta _{f} - \cos \theta _{i} ) }{\Delta t}[/tex]
Where [tex]\theta _{f} = 0[/tex] and [tex]\theta _{i} = 53[/tex] ( [tex]\theta = 37[/tex] angle between plane and magnetic field)
Average induced emf = [tex]\frac{80 \times (1-0.602) \times 1.10 \times 0.1 }{0.06}[/tex]
Average induced emf = [tex]58.4[/tex] V
