Answer:
Radius of circular path will be [tex]29.10\times 10^{-6}m[/tex]
Explanation:
Mass of electron [tex]m=9.1\times 10^{-31}kg[/tex]
Charge on electron [tex]q=1.6\times 10^{-19}C[/tex]
Speed of electron is given [tex]v=8.7\times 10^6m/sec[/tex]
Magnetic field is given B = 1.7 T
We have to find the radius of the circular path
Radius of circular path is equal to [tex]r=\frac{mv}{qB}[/tex] , here m is mass v is velocity q is charge and B is magnetic field
So [tex]r=\frac{9.1\times 10^{-31}\times 8.7\times 10^6}{1.6\times 10^{-19}\times 1.7}=29.10\times 10^{-6}m[/tex]
So radius of circular path will be [tex]29.10\times 10^{-6}m[/tex]
