Respuesta :
Answer:
[tex]\sum X_i = 219.8[/tex]
And we can calculate the mean with the following formula:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}= \frac{219.8}{27}= 8.141[/tex]
We can calculate the sample variance with this formula:
[tex]s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}= 2.819[/tex]
And the sample deviation would be given by:
[tex] s= \sqrt{s^2}=\sqrt{2.819}= 1.679[/tex]
Step-by-step explanation:
For this case we have the following data given:
7.9 9.7 9.7 8.7 7.0 7.2 11.3 11.8 7.3 8.1 8.0 11.6 6.8 9.0 6.3 7.0 7.4 8.7 6.8 5.8 7.8 7.7 6.3 7.0 7.7 6.5 10.7
Our variable of interest is given by X="flexural strength (MPa) for concrete beams of a certain type"
And for this case we know that [tex]\sum X_i = 219.8[/tex]
And we can calculate the mean with the following formula:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}= \frac{219.8}{27}= 8.141[/tex]
We can calculate the sample variance with this formula:
[tex]s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}= 2.819[/tex]
And the sample deviation would be given by:
[tex] s= \sqrt{s^2}=\sqrt{2.819}= 1.679[/tex]
