Answer:
5.313 L is the average volume of pollutant  reported by chemical engineer:
Explanation:
Volume of pollutant from Lincoln = 0.52 L
Volume of pollutant from Pinecrest = 9.777 L
Volume of pollutant of Pitt = 5.643 L
[tex]Average =\frac{\text{sum of observations}}{\text{Number of observations}}[/tex]
Average volume of pollutant  reported by chemical engineer:
[tex]=\frac{0.52L+9.777L+5.643L}{3}=5.313 L[/tex]