Answer:
Step-by-step explanation:
If the length and width of the poster are represented by variables [tex]l[/tex] and [tex]w[/tex] respectively, then we can set up the following equations based on the problem statement:
[tex]lw = 486[/tex]
[tex]l = 1.5w[/tex]
We can plug the second equation in the first to get the following:
[tex](1.5w)w = 486[/tex]
[tex]1.5w^{2} = 486[/tex]
[tex]w^{2} = 324[/tex]
[tex]w = 18[/tex]
Plugging this back into the first original equation, we can get the value of [tex]l[/tex]:
[tex]l(18) = 486[/tex]
[tex]l = 27[/tex]
From this, we know that the width is [tex]18[/tex] units and the length is [tex]27[/tex] units.
