Respuesta :

Answer:

Area of the figure= [tex]51.5feet^2[/tex]

Step-by-step explanation:

Area of the figure=Area of the middle rectangle+ Area the the two triangles

Area of the rectangle=Length*Width

[tex]Length= 8+3 =11 feet\\\\Width=4 feet[/tex]

[tex]Area = 11*4\\\\ =44 feet^2[/tex]

Area of the triangle with the height of 2 feet and base= 3 feet

Area= [tex]\frac{1}{2} *Base*Height[/tex]

=[tex]=\frac{1}{2} *3*2\\\\=\frac{1}{2}*6\\\\ =3 feet^2[/tex]

Area of the triangle with the Height=3 feet and Base= 3 feet

Area= [tex]\frac{1}{2} *Base*Height[/tex]

[tex]=\frac{1}{2}*3*3\\\\ =\frac{1}{2}*9\\\\ =4.5feet^2[/tex]

Total Area of the figure[tex]=44+3+4.5=51.5 feet^2[/tex]

Answer:

51.5  ft^2

Step-by-step explanation:

Area of the shape

We can solve this by dividing into shapes

area of rectangle

formula:

length * width

=(3+8 ) * 4

=44  ft^2

area of top triangle

[tex]\frac{1}{2} * base * height[/tex]

[tex]\frac{1}{2} * 3 * 2[/tex]

=3  ft^2

area of bottom triangle

[tex]\frac{1}{2} * base * height[/tex]

[tex]\frac{1}{2} * 3 * 3[/tex]

= 4.5  ft^2

total area of the shape :  

Area of rectangle + area of top triangle + area of bottom triangle

=44 + 3 + 4.5

=51.5  ft^2

the total area is 51.5  ft^2