The circle below is centered at the origin and has a radius of 4. What is its equation?

Answer:
C) x^2 + y^2 = 16
Step-by-step explanation:
since the radius is 4 this means that anywhere from the center of the circle to the edge of the circle is 4. hence :
place the horizontal line of the radius where y = 0 .
this means that if y = 0 , then x = 4
therefore :
x^2 + y^2
4^2 + 0^2
= 16
The circle below is centered at the origin and has a radius of 4. the equation would be C) x^2 + y^2 = 16
If a circle O has a radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane,
then, its equation is given as:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
The circle below is centered at the origin and has a radius of 4.
Since the place the horizontal line of the radius where y = 0.
This means that if y = 0 , then x = 4
therefore :
[tex]x^2 + y^2\\4^2 + 0^2\\= 16[/tex]
Therefore, the answer is C ) x^2 + y^2 = 16
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