Answer : The concentration of [CoCl₄]²⁻ is, [tex]2.95\times 10^{-3}M[/tex]
Explanation :
Using Beer-Lambert's law :
[tex]A=\epsilon \times C\times l[/tex]
where,
A = absorbance of solution = 0.935
C = concentration of solution = ?
l = path length = 0.71 cm
[tex]\epsilon[/tex] = molar absorptivity coefficient = [tex]446.9M^{-1}cm^{-1}[/tex]
Now put all the given values in the above formula, we get:
[tex]0.935=(446.9)\times C\times (0.71)[/tex]
[tex]C=2.95\times 10^{-3}M[/tex]
Therefore, the concentration of [CoCl₄]²⁻ is, [tex]2.95\times 10^{-3}M[/tex]
The concentration of CoCl42- is 0.0029 M
From the question, we have the following information;
molar absorptivity (ε) = 446.9 M-1 cm-1
path length(l) = 0.71 cm
absorbance (A) = 0.935
concentration (c) =?
Using the Beer - Lambert's law;
A = εcl
Making c the subject of the formula;
c = A/εl
Substituting values;
c = 0.935/446.9 M-1 cm-1 × 0.71 cm
c = 0.0029 M
The concentration of CoCl42- is 0.0029 M
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