Answer:
Answer is common ratio r= 4/3 option D)
Step-by-step explanation:
[tex]we \: want \: to \: find \: common \: ratio \\ here \: t1 = 3 \: t2 = 4 \: and \: t3 = \frac{16}{3} \\ in \: a \: geometric \: series \: \\ \frac{t2}{t1} = \frac{t3}{t2} = r \: (common \: ratio) \\ \frac{4}{3} = \frac{16}{3} \times \frac{1}{4} \\ \frac{4}{3} = \frac{4}{3} = r \: \\ therefore \: common \: ratio \: is \: \frac{4}{3} [/tex]
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