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Find the measures of the angles of an isosceles triangle whose equal sides measure 8 and whose altitude drawn to the base measures 4
Answer:
The measures of the angles of the isosceles triangle are 30°, 30° and 120°
Step-by-step explanation:
In a triangle whose sides a, b, c and angles A, B and C, where a is opposite to ∠A, b is opposite to ∠B, and c is opposite to ∠C, the given is
The height from ∠B to side b is 4 units
That means the length of the height is half the length of each equal sides, then there is a right triangle its hypotenuse is 8 and the side opposite to the base angle is 4, so we can find the measure of the base angle by using the rule sin(base angle) = [tex]\frac{altitude}{a}[/tex]
∵ The base angles are ∠A and ∠C
∵ a = c = 8
∵ The altitude to b is 4
∵ [tex]sin(A)=\frac{4}{8}=\frac{1}{2}[/tex]
- By using [tex]sin^{-1}[/tex]
∴ m∠A = [tex]sin^{-1}(\frac{1}{2})[/tex]
∴ m∠A = 30°
∵ m∠A = m∠C
∴ m∠C = 30°
Use the rule of the sum of the measures of the interior angle of a Δ is 180° to find m∠B
∵ m∠A + m∠C + m∠B = 180
∵ m∠A = m∠C = 30°
∴ 30° + 30° + m∠B = 180°
∴ 60 + m∠B = 180
- Subtract 60 from both sides
∴ m∠B = 120°
The measures of the angles of the isosceles triangle are 30°, 30° and 120°
